Prove Commutative Property of Convolution
GTU Sem 4 | Signals and Systems | Summer 2021 | Question 3(b) OR📘 Table of Contents
Introduction
In discrete-time signal processing, convolution is a key operation used to determine the output of Linear Time-Invariant (LTI) systems. One of the fundamental properties of convolution is its commutative property. In this post, we will prove that convolution is commutative, i.e., for two signals x(n) and h(n):
x(n) * h(n) = h(n) * x(n)
Commutative Property of Convolution – Signals & Systems Summer 2021 Question 3(b)OR
Definition of Convolution
The convolution of two discrete-time signals x(n) and h(n) is defined as:
y(n) = x(n) * h(n) = Σk=-∞∞ x(k) · h(n - k)
Proof: Commutative Property
We start with the definition of convolution:
y(n) = x(n) * h(n) = Σk=-∞∞ x(k) · h(n - k)
Now, perform a change of variable:
Let m = n - k ⟹ k = n - m
As k goes from -∞ to ∞, m also goes from ∞ to -∞, so we reverse the limits:
y(n) = Σm=∞-∞ x(n - m) · h(m)
Rewriting with standard summation order:
y(n) = Σm=-∞∞ h(m) · x(n - m)
This is equal to:
y(n) = h(n) * x(n)
Hence,
x(n) * h(n) = h(n) * x(n)
Conclusion
We have successfully shown that convolution in discrete time is commutative. This means the order of signals does not affect the result of convolution:
x(n) * h(n) = h(n) * x(n)
This property is very useful in analyzing LTI systems, as it allows us to treat the system and the input interchangeably in the convolution operation.
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